Equivalence and s-equivalence of vector-tensor Lagrangians
It will be proven that if a gauge-invariant Lagrangian density having the local form L = L(gij;Ai;Aij) is such that its Euler-Lagrange equations Ei(L) = 0 have the same set of solutions as Ei(L0) = 0, where L0 = g1/2F ijFij, then L and cL0 are equivalent for same constant c, i.e., Ei(L) = Ei(cL0). F...
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| Autores principales: | , , |
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| Formato: | Artículo publishedVersion |
| Publicado: |
1991
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| Acceso en línea: | http://hdl.handle.net/20.500.12110/paper_00222488_v32_n8_p2063_Lopez https://repositoriouba.sisbi.uba.ar/gsdl/cgi-bin/library.cgi?a=d&c=artiaex&d=paper_00222488_v32_n8_p2063_Lopez_oai |
| Aporte de: |
| Sumario: | It will be proven that if a gauge-invariant Lagrangian density having the local form L = L(gij;Ai;Aij) is such that its Euler-Lagrange equations Ei(L) = 0 have the same set of solutions as Ei(L0) = 0, where L0 = g1/2F ijFij, then L and cL0 are equivalent for same constant c, i.e., Ei(L) = Ei(cL0). From a previous result it follows that L = cL0 + D + eg1/2, where D is a divergence and e is a constant. © 1991 American Institute of Physics. |
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